Newton Meters to Foot-Pounds: 1 N·m equals 0.737562 ft·lb. To convert newton meters to foot-pounds, multiply by 0.737562 (ft·lb = N·m × 0.737562). For example, 10 N·m = 7.37562 ft·lb.
How to Convert Newton Meters to Foot-Pounds
To convert from newton meters to foot-pounds, multiply the value by 0.737562. The conversion is linear, meaning doubling the input doubles the output.
Conversion Formula
- Newton Meters to Foot-Pounds:
ft·lb = N·m × 0.737562 - Foot-Pounds to Newton Meters:
N·m = ft·lb ÷ 0.737562
Newton Meters to Foot-Pounds Conversion Chart
| Newton Meters (N·m) | Foot-Pounds (ft·lb) |
|---|---|
| 0.1 | 0.073756 |
| 0.25 | 0.184391 |
| 0.5 | 0.368781 |
| 1 | 0.737562 |
| 2 | 1.475124 |
| 3 | 2.212686 |
| 5 | 3.68781 |
| 10 | 7.37562 |
| 20 | 14.75124 |
| 25 | 18.43905 |
| 50 | 36.8781 |
| 100 | 73.7562 |
| 250 | 184.3905 |
| 1000 | 737.562 |
Understanding the Units
What is a Newton Meter?
The newton-meter is the SI derived unit of torque, equal to the moment produced by one newton acting at a perpendicular distance of one meter.
Common contexts: mechanical engineering, fastener specs.
What is a Foot-Pound?
A foot-pound (force) equals approximately 1.355818 newton-meters — the torque from one pound-force at one foot.
Common contexts: automotive (US), fastener torque (US).